tigerbarb Posted September 12, 2006 Report Share Posted September 12, 2006 Anyone know how to figure out how many gallons a hexagon tank is? Quote Link to comment Share on other sites More sharing options...
jvision Posted September 12, 2006 Report Share Posted September 12, 2006 Measure in CM (area of bottom x hight) then convert cm3 to gallons. Quote Link to comment Share on other sites More sharing options...
Rainmaker69 Posted September 13, 2006 Report Share Posted September 13, 2006 (edited) I found this on www.aquariumfish.net Hope it helps. The formula for volume is always the base times the height, which you measured 24.75". So all we need is the area of the base. Since all 6 panels in your aquarium are 12", the base is a so-called regular hexagon with all the sides measuring 12". The area of this regular hexagon is 6 times the area of an equilateral triangle with each side 12". Now think of a 12" equilateral triangle, and divide into two right triangles with one side 6" and hypotenuse 12". The other side will have a length equal to the square root of 12x12 - 6x6, which equals the square root of 144 - 36, which is the square root of 108, or about 10.4". The area of the right triangle is 1/2 x 6 x 10.4, and the area of the equilateral triangle will be twice as much, which is 6 x 10.4 = 62.4 square inches, so the area of the base of your aquarium is 6 x 62.4, or 374.4 square inches. The volume of your aquarium is the area of the base times the height = 374.4 x 24.75 = 9296.4 cubic inches. Now multiply by 0.00433 to convert cubic inches to gallons: 9296.4 x 0.00433 = 40.1 gallons, which answers your question. When you calculate something like this, and the answer is important, because you may use the answer to determine how much Quick Cure or Salt to add to your aquarium, then it's best to double check your calculation. Or you might end up forgetting that the equilateral triangle has two right triangles, and get an answer that is off by a factor of 2. Here is one way to double check the answer. The hexagonal base of your aquarium could fit inside a circle with a radius of 12" and have an area of about pi x 12 x 12 = 3.14 x 12 x 12 = 452.2 square inches which is somewhat bigger than the 374.4 square inches for the area of the hexagon inside the circle. So that checks. A circle with a radium 10.4" would fit inside the hexagon, and that circle would enclose an area of about pi x 10.4 x 10.4 = 3.14 x 10.4 x 10.4 = 327.8 square inches which is less than the 374.4 square inches for the area of the hexagon. So that checks too. Also the area of the hexagon should be about half-way between the area of the inner circle and the area of the outer circle. The areas are about 327.8, 374.4, and 452.2, so those numbers look about right. Now lets check these calculations with a measurement. Your aquarium is 24.75" tall. When you change 20% of water, as recommended repeatedly in this web site, you should remove 20% x 24.75 = 4.95, or about 5" of water. So measure down from the water surface 5" and put a mark on the glass with a marker pen. Now remove water down to the mark and keep track of how much water you remove. For example, you could use a clean one-pint measuring cup. You should get close to 64 pints, which is the same as 8 gallons, or 20% of the 40 gallons, that we calculated in your aquarium. (Be sure to thoroughly clean the measuring cup, when you finish using it.) You will probably measure less than 64 pints. Maybe you'll get 61. Because the measurements for your aquarium that you gave in your email were probably the outside measurements, and the water fills the inside of your aquarium. You could improve the calculations above by doing them again with the inside measurements, and perhaps subtracting the volume of the ornaments, etc. Click here for more about doing that. I hope this has thoroughly answered your question. Ok, just found this, lot's less work. http://tools.fishindex.com/ Edited September 13, 2006 by Rainmaker69 Quote Link to comment Share on other sites More sharing options...
Qattarra Posted September 13, 2006 Report Share Posted September 13, 2006 (edited) WOW ! Am I glad you added that link. I was reading through the instructions and my mind glazed over. HeHe . Thank you for the pointers. Edited September 13, 2006 by Qattarra Quote Link to comment Share on other sites More sharing options...
dunl Posted September 13, 2006 Report Share Posted September 13, 2006 I found this on www.aquariumfish.net Hope it helps.The formula for volume is always the ......blah blah blah....... I hope this has thoroughly answered your question. Ouch....ouch...ouch...make it stop hurting. Ouch. Quote Link to comment Share on other sites More sharing options...
tigerbarb Posted September 13, 2006 Author Report Share Posted September 13, 2006 Thanks for the help. I found that one site as well and had a similar experience! Quote Link to comment Share on other sites More sharing options...
Fish_Frenzy Posted September 13, 2006 Report Share Posted September 13, 2006 (edited) OMG! I just had a flashback to grade 10 math........wasn't pretty...may need therapy. I was told our hex is 50 gallons...think I will just "go with that" :shock: Tammy Edited September 13, 2006 by Fish_Frenzy Quote Link to comment Share on other sites More sharing options...
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